PHP
·
发表于 5年以前
·
阅读量：8301
#!/bin/bash
BEGIN {
print "The latest list of users and shells"
print "Userid Shell"
print "------ -----"
FS=":"
}
{
print $1 " " $7
}
END {
print "This concludes the listing"
}
#执行gawk命令截取/etc/passwd输出
#gawk -f gawk.sh /etc/passwd