post方式提交数据

var requestUrl="http://192.168.1.1:8080/test?type=test";
$.ajax({
    type : "post",
    async:true,
    url : requestUrl,
    data:{
            product : product,
            address : address,
            phone : phone,
            content : content,
        },
    dataType : "jsonp",
    success :function(data){
        //console.log("--------(xxxxx)-----success");
    },
    error:function(data){
        //console.log("error: (xxxxx)");
    }
});