PHP
·
发表于 5年以前
·
阅读量：8093
#!/bin/bash
#extracting options and parameters
while [ -n "$1" ]
do
case "$1" in
-a) echo "Found the -a option";;
-b) echo "Found the -b option";;
-c) echo "Found the -c option";;
--) shift
break;;
*) echo "$1 is not an option";;
esac
shift
done
count=1
for param in $@
do
echo "Parameter #$count: $param"
count=$[ $count + 1 ]
done