PHP
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发表于 5年以前
·
阅读量：8289
const arr1 = [1, 2, 3, 4, 5, 8, 9]
const arr2 = [5, 6, 7, 8, 9];
const result = arr1.concat(arr2.filter(v => !arr1.includes(v)))
console.log(result) //[1, 2, 3, 4,5, 8, 9]