PHP
·
发表于 5年以前
·
阅读量:8301
#!/bin/bash
# extracting command line options and values
while [ -n "$1" ]
do
case "$1" in
-a) echo "Found the -a option";;
-b) param="$2"
echo "Found the -b option, with parameter value $param"
shift;;
-c) echo "Found the -c option";;
--) shift
break;;
*) echo "$1 is not an option";;
esac
shift
done
count=1
for param in "$@"
do
echo "Parameter #$count : $param"
count=$[ $count + 1 ]
done