PHP
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发表于 5年以前
·
阅读量：8289
const arr1 = [1, 2, 3, 4, 5, 8, 9]
const arr2 = [5, 6, 7, 8, 9];
const difference = Array.from(new Set(arr1.concat(arr2).filter(v => !new Set(arr1).has(v) || !new Set(arr2).has(v))))
console.log(difference) //[ 1, 2, 3, 4, 6, 7 ]