PHP
·
发表于 5年以前
·
阅读量:8303
本文实例讲述了php实现统计网站在线人数的方法。分享给大家供大家参考。具体实现方法如下:
<?php
function getIpAddress() { // 取得当前用户的IP地址
if (getenv('HTTP_CLIENT_IP')) {
$ip = getenv('HTTP_CLIENT_IP');
} elseif (getenv('HTTP_X_FORWARDED_FOR')) {
$ip = getenv('HTTP_X_FORWARDED_FOR');
} elseif (getenv('REMOTE_ADDR')) {
$ip = getenv('REMOTE_ADDR');
} else {
$ip = $_SERVER['REMOE_ADDR'];
}
return $ip;
}
function writeover($filename,$data,$method = 'w',$chmod = 0){
$handle = fopen($filename, $method);
!handle && die("文件打开失败");
flock($handle, LOCK_EX);
fwrite($handle, $data);
flock($handle, LOCK_UN);
fclose($handle);
$chmod && @chmod($filename, 0777);
}
function count_online_num($time, $ip) {
$fileCount = './count.txt';
$count = 0;
$gap = 900; //15分钟不刷新页面就
if (!file_exists($fileCount)) {
$str = $time . "\t" . $ip . "\r\n";
writeover($fileCount, $str, 'w', 1);
$count = 1;
} else {
$arr = file($fileCount);
$flag = 0;
foreach($arr as $key => $val) {
$val= trim($val);
if ($val != "") {
list($when, $seti) = explode("\t", $val);
if ($seti ==$ip) {
$arr[$key] = $time . "\t" . $seti;
$flag = 1;
} else {
$currentTime = time();
if ($currentTime - $when > 900) {
unset($arr[$key]);
}else{
$arr[$key]=$val;
}
}
}
}
if ($flag == 0) {
array_push($arr, $time . "\t" . $ip);
}
$count = count($arr);
$str = implode("\r\n", $arr);
$str.="\r\n";
writeover($fileCount, $str, 'w', 0);
unset($arr);
}
return $count;
}
$time = time();
$ip = getIpAddress();
$online_num = count_online_num($time,$ip);
echo $online_num;
?>
希望本文所述对大家的php程序设计有所帮助。