Given a binary tree, you need to compute the length of the diameter of the tree. The diameter of a binary tree is the length of the longest path between any two nodes in a tree. This path may or may not pass through the root.
Example:
Given a binary tree
1
/ \
2 3
/ \
4 5
Return 3, which is the length of the path [4,2,1,3] or [5,2,1,3].
Note: The length of path between two nodes is represented by the number of edges between them.
找出二叉树中任意两个点之间的最远距离。
/**
* Definition for a binary tree node.
* type TreeNode struct {
* Val int
* Left *TreeNode
* Right *TreeNode
* }
*/
var levelRecord map[*TreeNode]int
func diameterOfBinaryTree(root *TreeNode) int {
levelRecord = make(map[*TreeNode]int)
getLevel(root) // NOTE: we only check the all nodes' level once
return helper(root)
}
func helper(root *TreeNode) int {
if root == nil || (root.Left == nil && root.Right == nil) {
return 0
}
withoutRoot := max(helper(root.Left), helper(root.Right))
withRoot := levelRecord[root.Left] + levelRecord[root.Right]
return max(withoutRoot, withRoot)
}
func getLevel(root *TreeNode) int {
res := 0
if root != nil {
res = max(getLevel(root.Left), getLevel(root.Right)) + 1
}
levelRecord[root] = res
return res
}
func max(a, b int) int {
if a > b {
return a
}
return b
}