Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.
Note: A leaf is a node with no children.
Example:
Given the below binary tree and sum = 22,
5
/ \
4 8
/ / \
11 13 4
/ \ \
7 2 1
return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.
判断是否存在一条从根节点到叶子节点的路径,该路径和为指定的数。
/**
* Definition for a binary tree node.
* type TreeNode struct {
* Val int
* Left *TreeNode
* Right *TreeNode
* }
*/
func find(root *TreeNode, tmp int, sum *int) bool {
if root == nil {
return false
}
tmp += root.Val
if (root.Left == nil) && (root.Right == nil) {
if tmp == *sum {
return true
} else {
return false
}
}
return find(root.Left, tmp, sum) || find(root.Right, tmp, sum)
}
func hasPathSum(root *TreeNode, sum int) bool {
return find(root, 0, &sum)
}